Find 4 consecutive odd numbers such that twice the sum of the least 2 numbers is 40 less than three times the sum of the greates
t two numbers
1 answer:
4 consecutive odd numbers....x, x + 2, x + 4, x + 6
2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7
x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13
ur numbers are : 7,9,11,13 <==
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A = 180 - 143 = 37
b = 143
c = a = 37
e = a = 37
f = 90 - 37 = 53
d = 180 - 85 - 37 = 58
g = 48
h = 180 -48 -48 = 84
k = 180 -84 = 96
m = 180 - 58 - 96 = 26
p = 180 - 26 - 85 = 69
r = 180 -69 = 111
s = p = 69
8/3=3x (cross multiplied to get this)
X=8/9 (divided both sides by 3)
Hope this helps :)
It is definitely d cause I can see
I think its x=27 im not sure sorry if its wrong!
10^6/10^-3 = 10^6-(-3) = 10^6+3 =
10^9