Find the value of the solubility product ksp for a saturated solution of mercury bromide, hgbr2, using the solubility of mercury
bromide. the solubility, s, of mercury bromide is 2.66×10−7 m. express your answer numerically to three significant figures.
1 answer:
When the reaction equation is:
HgBr2(s) ↔ Hg2+(aq) + 2Br-(aq)
So Ksp expression = [Hg2+] [Br-]^2
assume the solubility S = X = 2.66 x 10^-7 M
and from the reaction equation :
we can see that [Hg2+] = X
and the [Br-] = 2 X
so by substitution in Ksp formula will can get the Ksp value:
∴ Ksp = X * (2X)^2
= 2.66 x 10^-7 * (2*2.66 x 10^-7)^2
= 7.53 x 10^-20
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