Answer:
Here we have the function:
S(t) = 500 - 400*t^(-1)
Then the rate of change at the value t, will be:
S'(t) = dS(t)/dt
This differentiation will be:
S'(t) = -400/t^2
Then:
a) the rate of change at t = 1 is:
S'(1) = -400/1^2 = -400
The rate of change after one year is -400
b) t = 10
S'(10) = -400/10^2 = -400/100 = -4
The rate of change after 10 years is -4, it reduced as the years passed, as expected.
Good to see you here. Now back to the train.
Kaduna, K Lagos, L
Train leaves at 64 km/h
One hour late second train leaves Lagos at 96 km/h.
At the point they meet, if first train has been travelling for "x" hours. Second train has been travelling for (x-1) hour.
At the point the meet, the total distance travelled is equal to 624 km.
Therefore:
64(x) + 96(x-1) = 624
64x + 96x - 96 = 624
160x = 624+96
160x = 720 , x = 720/160 = 4.5
So when they meet, the first train which left Kaduna has travelled= 64x = 64*4.5= 288km from Kaduna.
So it is (624-288) km from Lagos. = 336 Km from Lagos.
Second train which left Lagos has travelled = 96(x-1) = 96(4.5-1) = 336km.
The second train is also 336 km away from Lagos.
Cheers.
Answer:
Step-by-step explanation: You put a line in the middle and it makes a triangle
The solution is (10,2) or x=10, y=2. Hope this helps :)