Answer:
1234567i9812345678912121212121
Answer:
60.0mL
Explanation:
For the process of titration , the formula we use is -
M₁V₁ = M₂V₂
Where ,
M₁ = initial concentration
V₁ = initial volume
M₂ = final concentration
V₂ = final volume .
Hence , from the question ,
The given data is ,
M₁ = 0.050 M
V₁ = 30.0mL
M₂ = 0.025 M
V₂ = ?
Now, to determine the unknown quantity , the formula can be applied ,
Hence ,
M₁V₁ = M₂V₂
Putting the respective values ,
0.050 M * 30.0mL = 0.025 M * ?
solving the above equation ,
V₂ = ? = 60.0mL
P = m*v
p = momentum
m = mass
v = velocity
p = (37 kg + 18 kg)*(1.2 m/s)
p = (55 kg)*(1.2 m/s)
p = 66 kg-m / s
Answer:
13.28 mol.
Explanation:
- We can use the general law of ideal gas:<em> PV = nRT.</em>
where, P is the pressure of the gas in atm (P = 1.32 atm).
V is the volume of the gas in L (V = 242.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K).
T is the temperature of the gas in K (T = 20.0° + 273 = 293.0 K).
∴ n = PV/RT = (1.32 atm)(242.0 L)/(0.0821 L.atm/mol.K)(293.0 K) = 13.28 mol.