All categories

3 years ago

Which fraction is bigger 5/6 or 8/9?

2 answers:

5 0

8/9 would be bigger.

This would be because, the number on the right side of the dash, is how many times 1 is split up, and the number on the left is the amount of split up chunks you would take.

In this case, 5/6, you would have 1 split into 6 chunks, and taking 5 out of 6 of them. 8/9 would be 1 split into 9 chunks, and taking 8 out of 9 of them.

Since there are more parts in 8/9 and you're taking almost all of them, it would be bigger then 5/6.

So therefore 8/9 is bigger.

dimulka [17.4K]3 years ago

4 0

5/6 = 5 ÷ 6 = 0.8333

8/9 = 8 ÷ 9 = 0.8888

so 8/9 is bigger.

hope this helped, God bless!

You might be interested in

Directions: Evaluate the solution 6) g(x) =- 2x + 5; Find g(-5) 6) in function notation?

harina [27]

Answer:

g(-5) = 15

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

g(-5) = -2(-5) +5 = 10 +5

g(-5) = 15

5 0

2 years ago

Leo's bank balances at the end of months 1, 2, and 3 are $1,500.00, $1,530.00, and $1,560.60, respectively. The balances form a

Rina8888 [55]

Not sure if im right but keep multiplying it and then you will get your answer, i have an answer but im afraid it might be a bit off, goodluck

6 0

2 years ago

Read 2 more answers

FIND (-8/3)+(-1/4)+(-11/6)+3/8-3

emmainna [20.7K]

Answer:

-7 3/8

Step-by-step explanation:

The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

$-\frac{8}{3}+\left(-\frac{1}{4}\right)+\left(-\frac{11}{6}\right)+\frac{3}{8}-3\\=-\frac{64}{24}+\left(-\frac{6}{24}\right)+\left(-\frac{44}{24}\right)+\frac{9}{24}-3\\\\=\frac{-64+(-6)+(-44)+9}{24} -3\\\\=\frac{-70+(-44)+9}{24} -3\\\\=\frac{-114+9}{24} -3\\\\=\frac{-105}{24}-3 \\\\=\frac{-35}{8}-3\\ \\=-4\frac{3}{8}-3\\\\=-7\frac{3}{8}$

So our solution is -7 3/8

8 0

2 years ago

100 POINTS!!!!!!!!!!!!!!!!!!!!!!!!

hodyreva [135]

<h3>Key points :-</h3>

✪ Both triangles will be proven similar by AA theorem i.e. Angle-Angle theorem.

✪ The symbol for similarity is ~.

✪ The symbol for congruency is ≅.

$\rule{300pt}{2pt}$

Detailed solution is attached!!

$\large{|\underline{\mathtt{\red{A}\blue{n}\orange{c}\pink{i}\blue{e}\purple{n}\green{t}\red{E}\blue{n}\orange{i}\green{g}\red{m}\purple{a}\pink{29}}}}$

6 0

1 year ago

Read 2 more answers

Given one zero of the polynomial function, find the other zeros.

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

You need to use synthetic division to do all of these. The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.

a. 3I 1 3 -34 48

I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.

First step is to bring down the first number after the bold line, 1.

3I 1 3 -34 48

_____________

then multiply it by the 3 and put it up under the 3. Add those together:

3I 1 3 -34 48

----------------------------

1 6

Now I'm going to multiply the 6 by the 3 after the bold line and add:

3I 1 3 -34 48

3 18

_________________

1 6 -16

Same process, I'm going to multiply the -16 by the 3 after the bold line and add:

3I 1 3 -34 48

3 18 -48

___________________

1 6 -16 0

That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

$x^2+6x-16=0$

Factoring that depressed polynomial will give you the remaining zeros. Because this was originally a third degree polynomial, there are 3 zeros as solutions. Factoring that depressed polynomial gives you the remaining zeros of x = -8 and x = 2

I am assuming that since you are doing synthetic division that you have already learned the quadratic formula. You could use that or just "regular" factoring would do the trick on all of them.

Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.

You got this!

4 0

2 years ago