133.25 is the awnser for this question
Answer:
Step-by-step explanation:
Given that tank has the shape of inverted circular cone
Height = 10 feet and radius = 4 feet
After water pumped out height = 5 ft
Hence volume of water pumped out =
Here we have r/h is constant always
Hence
Substitute to get volume of water pumped out =
Mass of water = density x volume =
Work done = force x displacement
= mass x accen x displacement
Here acceleration = gravity = 32.2 ft/sec^2
Displaement = height reduced = 5 ft
W=2912(32.2)(5)\pi =468832\pi foot -pound
Answer:
x = 26, 16
Step-by-step explanation:
( x-21) ^2 = 25
Take the square root of each side
sqrt(( x-21) ^2) = ±sqrt(25)
x-21 = ±5
Add 21 to each side
x-21+21 = 21±5
x = 21±5
x = 21+5 and x = 21-5
x = 26, 16
In order to invert a function, switch y and x in the definition, and solve for y again:
Solving for y, we have