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schepotkina [342]

2 years ago

10

Simplify the radical expression.

1 answer:

andrey2020 [161]2 years ago

6 0

√20 = √4x5 = 2√5

√56²= 56

√[150.(x³)(k⁴)] = √(6*25)(x².x).k⁴ ==>5xk²√6x

√[(14q) *2√(4q)] = 14(q√2²q) ==>28q√q

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PLEASE HELP!! I beg of yall

Delicious77 [7]

Answer:oop

Step-by-step explanation:

5 0

2 years ago

Yesterday, 20 guests at a hotel called for room service, and 60 guests did not call for room service. What percentage of the gue

Neko [114]

33.3% is the answer, I think

20/60 ---> 1/3, covert this to a percentage and it equals 33.3%

6 0

2 years ago

-4(9 + 6) = plz help me

Arlecino [84]

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5 0

2 years ago

Read 2 more answers

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is:

$y = \frac{1}{3}\cdot (2)^{2}-\frac{4}{3}\cdot (2) - 4$

$y = -5.333$

$(x,y) = (2, -5)$ does not belong to the function, the real point is $(x,y) = (2, -5.333)$ .

5 0

2 years ago

What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in

xeze [42]

ANSWER

$197 {in}^{2}$

EXPLANATION

The area of the two tra-pezoidal faces

$= 2 \times \frac{1}{2} \times (9 + 5) \times 5 = 70 {in}^{2}$

The area of the 5 by 6.4 rectangular face

$= 6.4 \times 5 = 32 {in}^{2}$

The area of the two square faces

$= 2(5 \times 5) = 50 {in}^{2}$

The area of the 9 by 5 rectangular face is

$= 9 \times 5 = 45 {in}^{2}$

The surface area of the design is:

$70 + 32 + 50 + 45=197 {in}^{2}$

6 0

2 years ago