Answer:
t = 2 seconds
Explanation:
In 2nd question, the question is given the attached figure.
Initial speed of the bus, u = 0
Acceleration of the bus, a = 8 m/s²
Final speed, v = 16 m/s
We need to find the time taken by the car to reach the stop. Acceleration of an object is given by :
t is time taken
The bus will take 2 seconds to reach the stop.
Answer:
Explanation:
From the concept of fluids mechanics we know that if a tank has a hole at the bottom, the equation that we need to use is:
Since we know gravity and its hight
Answer:
The first part can be solved via conservation of energy.
For the second part,
the free body diagram of the car should be as follows:
- weight in the downwards direction
- normal force of the track to the car in the downwards direction
The total force should be equal to the centripetal force by Newton's Second Law.
where because we are looking for the case where the car loses contact.
Now we know the minimum velocity that the car should have. Using the energy conservation found in the first part, we can calculate the minimum height.
Explanation:
The point that might confuse you in this question is the direction of the normal force at the top of the loop.
We usually use the normal force opposite to the weight. However, normal force is the force that the road exerts on us. Imagine that the car goes through the loop very very fast. Its tires will feel a great amount of normal force, if its velocity is quite high. By the same logic, if its velocity is too low, it might not feel a normal force at all, which means losing contact with the track.
Answer:
Velocity = 0.309 m/s
Along negative x axis
Explanation:
A pulse moving to the right along the x axis is represented by the wave function
y(x,t) = 2/ (x - 3t)² + 1
At t =0
y(x,0) = 2/ ((x - 3(0))² + 1)
=2 / (x² + 1)
At t = 1
y(x,t) = 2/ ((x - 3(1))² + 1)
= 2 /(( x - 3)² + 1)
At t = 2
y(x,t) = 2/ ((x - 3(2))² + 1)
= 2 /(( x - 6)² + 1)
For the pulse with expression y(x,t) = 4.5²
The Velocity is
V = 2.7 / 8.73
= 0.309 m/s