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2 years ago

7

Solve the following system.

2 answers:

Ilya [14]2 years ago

6 0

The answer is 3,6 this was easy

rusak2 [61]2 years ago

4 0

Y = x + 3 . . . (1)
4x + y = 18 . . . (2)

Putting (1) into (2) gives
4x + x + 3 = 18
5x = 18 - 3 = 15
x = 15/5 = 3
x = 3
y = x + 3 = 3 + 3 = 6

Solution = (3, 6)

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sp2606 [1]

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2 years ago

oksian1 [2.3K]

Answer:

9 units

Step-by-step explanation:

By the midsegment theorem,

$AB=\dfrac{KN+LM}{2}$

Since the ratio $LM:KN=1:5,$ then $LM=x,\ KN=5x$ and

$18=\dfrac{x+5x}{2}\\ \\18=\dfrac{6x}{2}\\ \\18=3x\\ \\x=6\\ \\LM=6\ units\\ \\KN=30\ units$

Draw two heights LE and MF. Quadrilateral ELMF is a rectangle, then EF = LM = 6 units.

Trapezoid KLMN is isosceles trapezoid (KL = MN), then KE = FN and

$KE=FN=\dfrac{KN-EF}{2}=\dfrac{30-6}{2}=12\ units$

Consider right triangle KLE. By the Pythagorean theorem,

$KL^2=LE^2+KE^2\\ \\15^2=LE^2+12^2\\ \\LE^2=15^2-12^2\\ \\LE^2=225-144=81\\ \\LE=9\ units$

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