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2 years ago

7

What is the derivative of this

1 answer:

skelet666 [1.2K]2 years ago

7 0

$\bf r(x)=\cfrac{3x-2}{2x+5}\implies \cfrac{dr}{dx}=\stackrel{quotient~rule}{\cfrac{3(2x+5)~~-~~(3x-2)2}{(2x+5)^2}}
\\\\\\
\cfrac{dr}{dx}=\cfrac{\underline{6x}+15\underline{-6x}+4}{(2x+5)^2}\implies \cfrac{dr}{dx}=\cfrac{19}{(2x+5)^2}$

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Help me please this is donr tomorrow and if i don't finish it my teacher will be so mad

Genrish500 [490]

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2 years ago

Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at $(x_1,y_1)$ and point Q at $(x_2,y_2)$ in the proportion a:b, we use the formula:

$x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1$

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

$x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1$

4 0

2 years ago

Where is EF to the nearest tenth??

Katena32 [7]

Answer:

37.7

Step-by-step explanation:

EF and ED define the Tangent of D

Tan(37) = side opposite D / side adjacent to D

Opposite means a line (FE) that is not connected to the angle. It is never the longest line (hypotenuse) in a Right Triangle

Adjacent means the leg that is connected to the angle, but is not the hypotenuse.

Tan(D) = opposite over adjacent

Opposite = x

Adjacent = 50

Tan(37) = 0.7536 rounded to 4 places, but I've kept the exact value in my calculator.

0.7536 = x / 50 Multiply both sides by 50

0.7536*50 = x

x = 37.6777

The nearest 1/10 is 37.7

6 0

2 years ago

A triangle has vertices A(1, 1), B(2, 4), and C(4, 2). Line p is parallel to side AB and contains point C.

kenny6666 [7]

Answer:

$p:y = 3x-10$

Step-by-step explanation:

We are given the following in the question:

A(1, 1), B(2, 4), C(4, 2)

i) Slope of AB

$A(1, 1), B(2, 4)\\\\m = \dfrac{y_2-y_1}{x_2-x_1}\\\\m = \dfrac{4-1}{2-1}=3$

Thus, slope of AB is 3.

ii) Point slope form

The point slope form of a line can be written as:

$y - y_1 = m(x - x_1)$

The point intercept form of line can be written as:

$y = mx + c$

The line is parallel to AB and contains point C(4, 2). Since line p is parallel to AB, line p will have the same slope as line AB

Putting values, we get,

$y - 2 = 3(x-4)\\y = 3x-12+2\\y = 3x-10$

which is the required slope intercept equation of line p.

4 0

2 years ago

Bess [88]

Answer:

ID

Step-by-step explanation:

UHH

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2 years ago