All categories

2 years ago

What times 3 gives you 16

2 answers:

7 0

I know the answer to this has already been given, but I just want to tell you how to work this out on your own using a formula.

So, say we want to find out what times 6 = 90. So instantly we want to find out the number of 6s that go into 90, because that is our answer.

So we do 90 divided by 6 we get 15.

So know we know that 15 6s fit into 9.

15 is our answer.

Margarita [4]2 years ago

4 0

Technically nothing times 3 get you 16 but 3 times 5 equals 15 which is the closest answer but the answer would be 5.3

You might be interested in

The area of a square quilt is 196 square inches. There is a smaller square patch on the quilt with an area of 49 square inches.

Makovka662 [10]

To find your answer you would find the perimeter of the small square which is 28.

You would then find the perimeter of the big square which is 56.

Next, you subtract 56 from 28 and get 28.

So the difference is 28 inches.

Hope this helps!!

5 0

2 years ago

Read 2 more answers

How can you tell if a fraction is a perfect square?

zimovet [89]

Answers: A fraction is a perfect square if it's reduced version (of an improper fraction if the number is greater than 1) has both numerator and denominator numbers that are perfect squares. IE: 25/36 is a perfect square because both 25 and 36 are perfect squares.

Step-by-step explanation:

So for example 5/25 is a perfect square but 2/5 wouldn't be a perfect square.

Tell me if this helped you

7 0

2 years ago

Plese help me guys !!

Westkost [7]

Answer:option d.

hope it helps you.

3 0

1 year ago

Read 2 more answers

2 2/7 multiplied by 5 1/6

labwork [276]

Answer:

11 17/21

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago