If 1 cm = 3 ft, then 5 cm = 5*3 = 15 ft.<==
Answer:
x = 6.39, y = 1.69 is the solution of the given equation system.
Step-by-step explanation:
Here, the given set of equation is:
5 x = 15 + 10 y ⇒ 5 x - 10 y = 15 ...... (1)
3 x +7 y = 31 ............. (2)
Now, the coefficient of x in first equation id 5 and in second is 3.
So, MULTIPLY (1) with 3 and (2) with -5 , we get:
15 x - 30 y = 45
-15 x- 35 y = -155
<u>ADD BOTH EQUATIONS ,</u> we get:
15 x - 30 y -15 x- 35 y = 45 - 155
or, -65 y = -110
or, y = 110/65 = 1.69
Put y = 1.69 in 3 x +7 y = 31 , we get:
3(x) + 7 (1.69) =31
⇒ 3 x = 19.17 or x = 6.39
Hence, x = 6.39, y = 1.69 is the solution of the given equation system
<span>A cross-section parallel to the base is a rectangle measuring 15 inches by 8 inches.
</span><span>A cross-section perpendicular to the base through the midpoints of the 8-inch sides is a rectangle measuring 6 inches by 15 inches.
</span>
<span>A cross-section not parallel to the base that passes through opposite 6-inch edges is a rectangle measuring 6 inches by greater than 15 inches.
the cross sections that are parallel and perpendicular will have the same measurements as the non-intersected sides. the last one will be a diagonal so the intersected edge is 6 and it creates a right triangle so it must be larger than 15 inches.
</span><span>
</span>
Answer:
See below
Step-by-step explanation:
If |x| < |y| and both are negative the x will be to the right of y on the number line. The point x is loser to the zero on the number line. We can illustrate this by supposing x = -3 and y = -6.
|x| = 3 and |y| = 6 and 3 < 6 but -3 on the number line is higher ( to the right) of -6 and closer to the zero.
|-8 1/3| = 8 1/3
|7 2/3| = 7 2/3
The absolute values of 8 1/3 > than absolute value of 7 2/3. The point 7 2/3 is closer to the zero on a number line.
The absolute value of F is greater than absolute value of E so E is closer to the zero line than F.
Answer:
the student who have a prime number is Maria
Step-by-step explanation:
