Answer:
2+6
2(+3)
Solution
Step-by-step explanation:
f"(x)=2
integrating
f'(x)=2x+c
f'(1)=2+c=4
c=4-2=2
f'(x)=2x+2
f(x)=2x^2/2+2x+a
f(x)=x^2+2x+a
f(2)=-2
(2)^2+2(2)+a=-2
4+4+a=-2
a=-2-8=-10
f(x)=x^2+2x-10
do its ??
Hence,
But,
Simplifying,
=