Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid =
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid =
Or, The surface area of right regular hexagonal pyramid =
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 ×
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer
This is false, because the equation is then 12=2, which is incorrect.
Hope this helps!
~ThePirc
Answer:
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According to the basic trigonometric equation for right angle triangles:
Sin(x) = opp/hyp
so...
Sin(60) = 4(sqrt(3))/x
x = 4(sqrt(3))/sin(60)
x = 6.928.../0.866...
x = 8
Answer: 8
Step-by-step explanation: the given expression is 2n-3
so when n=1, we will get, 2(1)-3=2-3=-1
when n=2, we will get, 2(2)-3= 4-3=-1
when n=3, we will get 2(3)-3= 6-3=3
when n=4, we will get 2(4)-3 = 8-3=5
so the required result of expansion is -1+1+3+5=8
answer is 8.
hope that helped!