The quickest way to do this is to plug the first b-value from each table into the equation to find p-value. Then compare your answer with the p-value from the table to find the one that is greater than your answer.
p = 3.25b
<u>Equation </u> <u>Table</u> <u>Table compared to Equation</u>
Table A: p = 3.25(1) = 3.25 p = 2.75 <
Table B: p = 3.25(1.5) = 4.875 p = 3.75 <
Table C: p = 3.25(2) = 6.50 p = 7.00 >
Table D: p = 3.25(2.5) = 8.125 p = 10.00 >
Table E: p = 3.25(3) = 9.75 p = 11.25 >
Table F: p = 3.25(3.5) = 11.375 p = 10.50 <
Answer: C, D, and E
Answer:
See below
Step-by-step explanation:
Both horses travel 0 miles in 0 minutes. We can see this on the graph where both lines start at the 0 in the bottom left corner. For the purpose of writing the equations this also shows us that the y-intercept is 0. In a slope-intercept equation, y=mx+b, that number is the b. b is zero in both equations, so we don't need to write anything for that.
For horse A, we can see on the graph that at 4 minutes, horse A has traveled 1 mile. Also, confirming this rate, at 8 minutes, it went 2 miles. This will help us find the rate. The rate will be the number we fill in for the m in the y=mx+b equation. Horse A goes 1mile every 4 minutes. That is a rate of 1/4 miles per minute. So Horse A's equation will be
y = (1/4)x You can make it more *intuitive* possibly by using m for miles and t for time instead, like this:
m = (1/4)t
Horse B is a little bit faster, and you can see this bc the line is a little bit steeper. It goes 2 miles in 5 minutes (confirm you can see it goes 4 miles in 10 minutes)
So Horse B's equation is
y = (2/5)x
or miles = (2/5)time
Mathematically, the equations are the same whether you use x,y or m,t
If Horse A runs for 12 minutes then it will run
miles = (1/4)minutes
miles = (1/4)(12)
miles = 3
If Horse B runs for 12 minutes, then it will run
miles = (2/5)minutes
miles = (2/5)12
miles = 4.8
Answer:
Exp Date: 1/17/2017
Exp Time: 4:00am
Prep Date: 12/3/2016
Prep Time: 4:00am
Initials: 12/7/2016
Step-by-step explanation:
A well-detailed version of the question has been uploaded in form of an image for easier understand.
Looking at the question, it was said that she received her store order on 12/3/2016 at 4am, this implies that the prep date and time are 12/3/2016 and 4am respectively. Also, it was said that the expiration date was printed on the product and it is 1/17/2017. Obviously, the expiration time would also be 4am because it was prepared at 4am and if we calculate in. 24hours we would get 4am at the expiration date as well. Lastly, we were told she opened the product she received on 12/7/2016 which is the initial date the product was used. From all these we can deduce the following:
Exp Date: 1/17/2017
Exp Time: 4:00am
Prep Date: 12/3/2016
Prep Time: 4:00am
Initials: 12/7/2016
9.) 155,952 were in town
B.) yes he is correct because 60%= 164,160 which is less than the amount of votes
Answer:
The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
560 random tests conducted, 26 employees failed the test. This means that
98% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 98% confidence interval for the proportion of applicants that fail the test is (0.025, 0.067).