Answer:
70 yd.
Step-by-step explanation:
The three streets at the intersection form a right triangle.
For a right triangle, the length of the longest side (called hypothenuse) is given by Pythagorean's theorem:
![h=\sqrt{x^2+y^2}](https://tex.z-dn.net/?f=h%3D%5Csqrt%7Bx%5E2%2By%5E2%7D)
where
x is the length of the 1st side
y is the length of the 2nd side
h is the length of the hypothenuse
Here we want to find the hypothenuse.
We have:
x = 42 yd (length of the 1st side)
y = 56 yd (length of the 2nd side)
Substituting, we find h:
![h=\sqrt{42^2+56^2}=70 yd](https://tex.z-dn.net/?f=h%3D%5Csqrt%7B42%5E2%2B56%5E2%7D%3D70%20yd)
So in order to get rid of the cubed roots, you must cube each side of the equation. what you do to one side you do to the other at all times. so when you cube a cubed root, you get whats in side. so after the first step, you should get x+5=8(2x+6) now distribute the 8 on the right side of the equation and get x+5=16x+48solve for x and get x=-43/15
A , b & c ?
lmk if i’m wrong tho
Your question is:
![\frac{8u}{u^2-18u+81} -\frac{72}{u^2-18u+81}](https://tex.z-dn.net/?f=%5Cfrac%7B8u%7D%7Bu%5E2-18u%2B81%7D%20-%5Cfrac%7B72%7D%7Bu%5E2-18u%2B81%7D)
Then, the above formula equate:
![\frac{8u-72}{u^2-18u+81}](https://tex.z-dn.net/?f=%5Cfrac%7B8u-72%7D%7Bu%5E2-18u%2B81%7D)
Factor out 8 from the numerator we get:
![\frac{u-9}{u^2-18u+81}](https://tex.z-dn.net/?f=%5Cfrac%7Bu-9%7D%7Bu%5E2-18u%2B81%7D)
Factorization of the denominator:
![\frac{u-9}{(u-9)^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bu-9%7D%7B%28u-9%29%5E2%7D)
Simplifying the numerator and the denominator by (u-9) we get: