Match the functions with their ranges. Tiles y = 3sin(x − π) (-∞, ∞) y = 1 − sin(x) [-1, 7] y = 3 + 4cos(x − π) [-3, 3] y = 2 +
2 answers:
<h2>
Answer: </h2>
Function Range
y = 3sin(x − π) [-3,3]
y = 1 − sin(x) [0,2]
y = 3+4cos(x − π) [-1,7]
y = 2 + cot(x) (-∞,∞)
<h2>
Step-by-step explanation: </h2>
We know that the range of:
y= sin x and y=cos x is : [-1,1]
and the range of the cot function is : (-∞,∞)
1)
y = 3sin(x − π)
As we know that:
-1≤ sin x ≤1
⇒ -1 ≤ sin(x-π) ≤1
⇒ -3 ≤ 3sin(x-π) ≤3
Hence, Range is [-3,3]
2)
y = 1 − sin(x)
-1≤ sin x ≤1
⇒ 1 ≥ -sin x ≥ -1
( since on multiplying by -1 the inequality gets reversed in sign)
It could be written as:
-1 ≤ -sin x ≤ 1
⇒ 1-1 ≤ 1-sin x ≤ 1+1
⇒ 0 ≤ 1-sin x ≤ 2
Hence, Range=[0,2]
3)
y = 3 + 4cos(x − π)
As we know that:
-1 ≤ cos x ≤ 1
-1 ≤ cos (x-π) ≤ 1
so, -4 ≤ 4 cos(x-π) ≤ 4
so, 3-4≤ 3+4cos(x-π) ≤ 4+3
⇒ -1≤ 3+4cos(x-π) ≤ 7
Hence, Range= [-1,7]
4)
y = 2 + cot(x)
as we know that:
cot x lie between (-∞,∞)
so adding a constant won't change it's range.
It remains same (-∞,∞)
By graphing each function, we can find the range of each one
So,
From figure 1: The range of y = 3sin(x − π) ⇒⇒⇒⇒⇒ [-3, 3]
From figure 2: The range of y = 1 − sin(x) ⇒⇒⇒⇒⇒ <span>[0, 2]
</span> From figure 3: The range of y = <span>3 + 4cos(x − π) ⇒⇒⇒⇒⇒ </span><span>[-1, 7]
</span> From figure 4: The range of y = <span>2 + cot(x) ⇒⇒⇒⇒⇒ </span>(-∞, ∞)
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