Can people please help me on this
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Answer:
The equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:
- y = 3x-13
Step-by-step explanation:
Given the equation
y + 5 = 3(x - 1)
Writing in the slope-intercept form
y=mx+b
where m is the slope and b is the y-intercept
y = 3(x-1) -5
y = 3x-3-5
y = 3x - 8
Thus, the slope = m = 3
We know that the parallel lines have equal slopes.
So, the slope of a parallel line is also 3
Using the point-slope form of the line equation
substituting the values m = 3 and the point (3, -4)
y-(-4)=3(x-3)
y+4 = 3x-9
y = 3x-9-4
y = 3x-13
Thus, the equation for a line that is parallel to y + 5 = 3(x - 1) and goes through the point (3,-4) will be:
- y = 3x-13