The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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Answer:
1) c. 11
Step-by-step explanation:
2) b. 4x² + 4
I hope these are correct its been a while since ive done these.
X=2.5
Because y ok get 5x-8 for the triangle and x+2 for the square set them up to 5x-8=x+2 and you solve yo get 4x=10 and once you divide you get 2.5
Answer:
255 5,6 7,78
Step-by-step explanation:
C=πd where C=circumference, π=the constant pi, and d=diamter
d=C/π and since we are told that C=9π
d=9π/π
d=9