Answer:
Hence proved triangle ADE ≅ triangle BCE by Side Angle Side congruent property.
Step-by-step explanation:
Given:
AD ⊥ AB CD
BC ⊥ AB CD
AD = BC
∴ ∠ A = ∠ B = ∠ C = ∠ D =90°
∠ EDC = ∠ ECD
Solution
∠ C = ∠ BCE + ∠ ECD⇒ equation 1
∠ D = ∠ ADE + ∠ EDC⇒ equation 2
∠ C = ∠ D (given)
Substituting equation 1 and 2 in above equation we get
∠ BCE + ∠ ECD = ∠ ADE + ∠ EDC
But ∠ EDC = ∠ ECD (given)
∴ ∠ ADE = ∠ BCE
ED = EC (∵ base angles are same triangle is isosceles triangle)
Now, In Δ ADE and Δ BCE
AD =BC
∠ ADE = ∠ BDE
ED = EC
∴ By Side Angle Side congruent property
Δ ADE ≅ Δ BCE
x = 4
Step-by-step explanation:
2x² - 1 > 6x
2(4)²-1 > 6(4)
2(16)-1 > 24
32-1 > 24
31 > 24
The mean temperature of the orange juice is 5 °F <u>greater than</u> the mean temperature of the water
<h3>Calculating Average</h3>
From the question, we are to calculate how much greater the mean temperature of the orange juice is than the mean temperature of the water
From the given chart,
Mean temperature of orange juice =
Mean temperature of orange juice =
Mean temperature of orange juice = 73.33 °F
Mean temperature of water =
Mean temperature of water =
Mean temperature of water = 68.33 °F
Difference in temperature = 73.33 °F - 68.33 °F
Difference in temperature = 5 °F
Hence, the mean temperature of the orange juice is 5 °F <u>greater than</u> the mean temperature of the water
Learn more on Calculating average here: brainly.com/question/17102414
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