Answer:
The answer to your question is 242 ml
Explanation:
Data
HI 0.211 M Volume = x
KMnO₄ 0.354 M Volume = 24 ml
Balanced Chemical reaction
12HI + 2KMnO₄ + 2H₂SO₄ → 6I₂ + Mn₂SO₄ + K₂SO₄ + 8H₂O
Process
1.- Calculate the moles of KMnO₄ 0.354 M in 24 ml
Molarity = moles / volume (L)
moles = Molarity x volume (L)
moles = 0.354 x 0.024
moles = 0.0085
2.- From the balanced chemical reaction we know that HI and KMnO₄ react in the proportion 12 to 2. Then,
12 moles of HI --------------- 2 moles of KMnO₄
x --------------- 0.0085 moles of KMnO₄
x = (0.0085 x 12)/2
x = 0.051 moles of HI
3.- Calculate the milliliters of HI 0.211 M
Molarity = moles/volume
Volume = moles/molarity
Volume = 0.051/0.211
Volume = 0.242 L or Volume = 242 ml
This problem is asking for the percent by mass of hydrogen in hydrofluoric acid. At the end, the answer turns out to be D. 5% as shown below:
<h3>Percent compositions:</h3>
In chemistry, percent compositions are used for us to know the relative amount of a specific element in a compound. In order to do so for hydrogen, we use the following formula, which can also be applied to any other element in a given compound:
Where stands for the atomic mass of hydrogen and for the molar mass of hydrofluoric acid. In such a way, we plug in the atomic masses of hydrogen (1.01 g/mol) and fluorine (19.0 g/mol) to obtain:
Learn more about percent compositions: brainly.com/question/12247957
Answer:Minerals form when rocks are heated enough that atoms of different elements can move around and join into different molecules. Minerals are deposited from salty water solutions on Earth's surface and underground
Explanation:
Answer:
The balanced chemical equation:
Heat of combustion per gram of phenol is 32.454 kJ/g
Heat of combustion per gram of phenol is 3,050 kJ/mol
Explanation:
Heat capacity of calorimeter = C = 11.66 kJ/°C
Initial temperature of the calorimeter =
Final temperature of the calorimeter =
Heat absorbed by calorimeter = Q
Heat released during reaction = Q'
Q' = -Q ( law of conservation of energy)
Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)
Heat of combustion per gram of phenol:
Molar mass of phenol = 94 g/mol
Heat of combustion per gram of phenol: