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3 years ago

What did Ernest Rutherford s gold foil experiment demonstrate about atoms?

1 answer:

mote1985 [20]3 years ago

6 0

Rutherford performed gold foil experiment to understand that how negative and positive particles could Co exist in an atom. He bombarded alpha particles on a 0.00004 cm thick gold foil.

He proposed a planetary model of the atom and concluded following results and demonstrated that,
1. An atom produces a line spectrum.
2. An Electron revolves around the nucleus without any orbits.
3. Since most of the particles passed through the foil undeflected it means that most of the volume occupied by an atom is empty.
4. An Atom as a whole is neutral.
5. The deflection of few particles on the foil suggested that there is center of positive particles in an atom called the nucleus of the atom.
6. The complete rebounce of few particles on the gold foil suggested that the nucleus is very dense and hard.

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At stp potassium is classified as?

vekshin1

At STP, potassium is classified as a solid specifically a metallic solid. At these conditions, the element is neither a molecular solid nor an ionic solid since both needs electron movement. Potassium exists in its metallic form. Hope this answers the question.

5 0

2 years ago

An anhydrous sample of CaCO3 (100.089 g/mol) weighing 0.9849 g was quantitatively transferred into a 250.0 mL volumetric flask h

Katyanochek1 [597]

The molarity of CaCO₃ in the final solution is equal to 0.015 M.

Explanation:

When we add HCl over CaCO₃ we have the following chemical reaction:

CaCO₃ + 2 HCl → CaCl₂ + H₂CO₃

H₂CO₃ (is not stable) → CO₂ + H₂O

number of moles = mass / molecular weight

number of moles of CaCO₃ = 0.9849 / 100.089 = 0.0098 moles

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume (L)

number of moles of HCl = 12 × 0.001 = 0.012 moles

From the reaction we see that 1 mole of CaCO₃ will react with 2 moles of HCl so the limiting reactant will be HCl. Knowing this we formulate the following reasoning:

if 1 mole of CaCO₃ will react with 2 moles of HCl

then X moles of CaCO₃ will react with 0.012 moles of HCl

X = (0.012 × 1) / 2 = 0.006 moles of CaCO₃

The number of moles of CaCO₃ which remain unreacted are equal to 0.0098 (initial quantity) - 0.006 (reacted with HCl) = 0.0038 moles.

Now the molarity of CaCO₃ in the final solution:

molar concentration = number of moles / volume (L)

molar concentration of CaCO₃ = 0.0038 / 0.250 = 0.015 M

Learn more about:

molar concentration

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4 0

2 years ago

Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.1 kW/m2 . How long does it take for 1.91

Stels [109]

Answer:

1.736 × 10⁶

Explanation:

Data provided in the question:

Intensity of the energy received from the sun = 1.1 kW/m² = 1.1 × 10³ W/m²

Energy required to arrive = 1.91 × 10⁹ J

Area at the surface = 1 m²

Now,

we know that

Energy = Intensity × Area × Time

1.91 × 10⁹ = ( 1.1 × 10³ ) × 1 × Time

Time = [ 1.91 × 10⁹ ] ÷ [ 1.1 × 10³ ]

Time = 1.736 × 10⁶

3 0

2 years ago

What do scientist do to easily share measurement data they can understand

Jobisdone [24]

1. They use the same measuring system (metric)

2. Clearly and properly collect and record data, recording the procedure and results

3. Releasing the data into the public, letting everyone have access to it

maybe, I don't know what answer your teacher wants

3 0

2 years ago

An ideal gas has a volume of 18.25 L at a temperature of 15.9 °C. The temperature of the gas is raised to 40.7 °C while the numb

Fynjy0 [20]

Answer:

V₂ = V₁ / T₁ * T₂ . If you prefer to set the final volume and want to estimate the resulting temperature, then the equation of Charles' law changes to: T2=T1/T1 multiplied by v^2.

8 0

1 year ago

Read 2 more answers