<span>-2x + 8 + 5x > 2x + 1
3x + 8 > 2x + 1
x > -7
answer
D) - 5</span>
We're minimizing
subject to
. Using Lagrange multipliers, we have the Lagrangian
with partial derivatives
Set each partial derivative equal to 0:
Subtracting the second equation from the first, we find
Similarly, we can determine that
and
by taking any two of the first three equations. So if
determines a critical point, then
So the smallest value for the sum of squares is
when
.
Answer:
1/6^4.
Step-by-step explanation:
Multiply denominators.
6*6*6*6 = 1,296
Your answers are 1/6^4 and 1/1296.
Answer: 20 : 50 (m1 = 1) 40 : 100 (m2 = 2) 60 : 150 (m3 = 3) 80 : 200 (m4 = 4) 100 : 250 (m5 = 5) . Bababoi
Hope I helped
Step-by-step explanation: