Answer:
5 cm
Step-by-step explanation:
Let's assume this is a number line were given.
Distance of S from 0 = 4 units
Distance of T from 0 = 9 units
Length of ST = the difference between T and S
ST = |9 - 4| = 5 units = 5 cm
This means S and T are 5 cm apart.
The surface area will increase by a factor of 49/16
F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
The LCM is: <span>2,7,7,2,0.</span>
