<h3>Given</h3>
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
<h3>Find</h3>
The area of each figure, rounded to the nearest integer
<h3>Solution</h3>
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
for the first term:
n= 1 there is 1 item
n=2 there are 2+1 = 3 items
n = 3 there are 3+2+1 = 3+2 = 6 items
n = 4 there are 4+3+2+1 = 4+6 = 10 items
We are adding the "n" term each time
n = 5 10+5 = 15
n= 6 15+6 = 21
n = 7 21+7 = 28
n = 8 28+8 = 36
There would be 36 items in the 8th step
What is the median of the following numbers? 4, 5, 5, 2, 1, 3, 4, 5, 4, 4, 4, 7
Katen [24]
Answer:
4
Step-by-step explanation:
Rewrite is order going from least to greatest.
1, 2, 3, 4, 4, 4, 4, 4, 5, 5, 5, 7
Find the middle number.
Because there are an even amount of numbers you have to take the two middle numbers which are 4 and 4 add them which gives you 8 and then divide that by 2( because you added two numbers.)
Therefore the answer is 4
