Answer:
8 seconds.
Step-by-step explanation:
To solve this question, we need to find the time, , when , that is, when the height of the object above the ground is 0 feet.
Substituting feet per second and gives the quadratic:
Since 128 is divisible by 16, it can be reduced to .
We must now solve for .
We can easily see that one answer to the equation is 0,
(we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.
The second answer, is also easy to see by inspection:
.
Therefore the object lands 8 seconds after it is thrown.
Answer:
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Answer: Choice B)
Explanation:
You mentioned there isn't a diagram to go with this, but I'm assuming that this problem is referring to a previous problem you posted. In that problem, it mentions that point W is at (1,-2). If we apply the scale factor 3, then we're tripling each coordinate. That means x = 1 becomes x = 3, and y = -2 becomes y = -6
We can write it like this:
(1,-2) ---> 3*(1, -2) = (3*1, 3*(-2) ) = (3, -6)
Only choice B has W'(3,-6) so this is likely the final answer.
If we apply this dilation to every point, then that effectively makes quadrilateral W'X'Y'Z' to be three times longer and taller than compared to quadrilateral WXYZ. In other words, its side lengths are 3 times longer.
Answer:
(D) -40
Step-by-step explanation:
Hope it helps.
According to me it is correct.
But please if it is wrong let me know.
3.1
the number of trucks reading horizontally from the vertical scale is
2 + 2 + 3 + 3 + 3 + 4 + 5 = 22
average number of trucks = = 3.1 ( to 1 dec. place)