Question

Write an equation of a line that is perpendicular to y = -5x + 2 and passes through (10,8).

Answer 1

Equation of required line is:

$y=\frac{1}{5}x+6$

Step-by-step explanation:

We need to write an equation of a line that is perpendicular to y = -5x + 2 and passes through (10,8).

The standard form of slope-point form is:

$y=mx+b$

Where m is the slope and b is the y-intercept

Comparing the given equation  y = -5x + 2 with standard form:

The slope m = -5

Since the lines are perpendicular so, the slope of required line will be -1/m

So, slope =m = 1/5

Now we need to find b (y-intercept)

We are given the point (10,8) and slope = 1/5

Putting values in formula:

$y=mx+2\\8=1/5(10)+b\\8=2+b\\b=8-2\\b=6$

So, value of b=6

So, Equation of required line is:

$y=\frac{1}{5}x+6$

Keywords: Point slope form

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