Let the speed off the walk way be x and speed of the walkway be y
x+y=6....i
x-y=2....ii
adding the above equation we get:
2x=8
thus
x=4 ft/s
and
y=6-4=2 ft/s
thus the speed off the walk way is 4 ft/s
the speed of the moving walkway is 2 ft/s
X-20 = Y+20........ X-Y = 20+20........
X-Y = 40
AND
2Y-44=X+22............. Y-X= 44+22
Y-X=66
NOW, LET'S FIND X AND Y FROM THESE TWO EQUATIONS....
X-Y =40
Y-X= 66
IF WE COLLECT ....... 2Y = 106 AND Y = 53
THEN, USE Y IN ANY EQUATIONS FOR FINDING X
X-53 = 40 ..... X= 53+40 .......... X= 93
X= 93
Y=53
Answer:
B. There is an association because the value 0.15 is not similar to the value 0.55
Step-by-step explanation:
Based on the above picture, for the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.
The conditions that satisfy whether there exists an association between conditional relative frequencies are:
1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.
2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.
For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45
We can conclude that there is an association because the value 0.15 is not similar to the value 0.55
You have to consider the “ends” of the x-axis, the far right (for infinitely large values of x) and left (for infinitely small values of x) of the graph.
From the diagram above you can see that:
- When
then 
(notice that as the values of x get smaller and smaller, the graph gets closer and closer to the line y=1); - When
then 
(notice that as the values of x get larger and larger, the graph gets closer and closer to the line y=1).
Answer: correct choice is D.
