Mr. Otsuki has 25 bills worth $300. He has $5, $10, and $20 bills. How many of each type of bill could he have if he has exactly
ten $20 bills and at least nine $5 ...
1 answer:
Answer:
Mr. Otsuki could have:
10 $20 bills
5 $10 bills
10 $5 bills
but there are many other ways.
Step-by-step explanation:
We already know that Mr. Otsuki already has at least $245.
10 $20 bills - $200
at least 9 $5 bills - $45
300 - 245 = 55
55 can be made up in many different ways
5 tens + 1 five
9 fives+ 1 tens
4 tens + 3 fives
5 fives+ 3 tens
2 tens + 7 fives
So there are like five answers to this question:
A.
10 $20 bills
5 $10 bills
10 $5 bills
B.
10 $20 bills
1 $10 bills
9 $5 bills
C.
10 $20 bills
4 $10 bills
3 $5 bills
D.
10 $20 bills
3 $10 bills
5 $5 bills
10 $20 bills
2 $10 bills
7 $5 bills
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Answer:
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Step-by-step explanation:
3(-10)-5(6)
-30-30 = -30+-30
-30+-30= -60
The answer is -60
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Hope this helps! If you have any questions, feel free to ask.
Theres nothing we can do to hhelp u bruh
Answer: 7,280
Step-by-step explanation:
If we take the wall that is feet high and use 1,820 bricks we multiply to get the answer of 7,280. ;) Hope this helps
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