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3 years ago

What is 28 division 4

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

8 0

Answer:

Step-by-step explanation:

frosja888 [35]3 years ago

8 0

Answer:

Step-by-step explanation:

28 / 4 = 7

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Given f(x)=x2+14x+40 . Enter the quadratic function in vertex form in the box.

sammy [17]

Please indicate exponentiation using " ^ " Thanks.

f(x)=x2+14x+40 => f(x)=x^2+14x+40

Next, complete the square:

f(x)=x^2+14x+ 49 - 49 +40 = (x+7)^2 - 9

Write this in the form y = (x+7)^2 - 9 or y + 9 = (x+7)^2
Comparing this result to y = a(x-h)^2 + k, we see that h = -7 and k=-9

In vertex form, the equation is y + 9 = (x+7)^2 and the vertex is at (-7, -9).

8 0

3 years ago

WILL MARK BRAINLIEST!!! Can someone help me wit des two questions?

Airida [17]

Answer:

The answer to the first question is B.) The student should have subtracted the 4 first, instead of adding, because it is positive originally. And the answer to the second one is D.) Distribute the -2.

Step-by-step explanation:

Hope this helps! :)

7 0

2 years ago

If you are reading this please help!!!!

Soloha48 [4]

Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=12 x^2+18x-10 x-15$

$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=3x^{3}+15 x^2-6x-x^{2}-5 x+2$

Add or subtract like terms together.

$=3x^{3}+14 x^2-11x+2$

The answer for multiplying polynomials:

$1. -12 x^{5}+21 x^{2}$

$2. \ 12 x^2+8x-15$

$3. \ 3x^{3}+14 x^2-11x+2$

3 0

2 years ago

(5 pts) A quadratic function f is given by f(x) = ax2 + bx + c where a is not 0. Select all

Vsevolod [243]

Answers:

a) True. Plug in x = 0 and it leads to y = c. Therefore, the point (0,c) is on the parabola.
b) False. Plug in y = 0 and apply the quadratic formula. One x intercept may sometimes be x = c, but it could easily be other values as well. Or perhaps you may not get any real number solutions at all. See part d) below.
c) True. If a < 0, then the leading coefficient is negative. Overall, both endpoints will tend toward negative infinity to produce a parabola that opens downward.
d) False. The quadratic may have one x intercept or it may not have any x intercepts at all. It depends on what the discriminant d = b^2 - 4ac is equal to. If d < 0, then we have no x intercepts. If d = 0, then we have exactly 1 x intercept. If d > 0, then we have two different x intercepts.
e) True. The vertex's x coordinate is -b/(2a). If b = 0, then the x coordinate of the vertex is 0. The vertical line x = 0 is directly on top of the y axis.

8 0

2 years ago

What is the gcf of 12x^4+18x^2

kari74 [83]

12x^4+18x^2

= 3x^2 (4x^2+6)

Thus, the greatest common factor is 3x^2

4 0

2 years ago