Answer: 68
Explanation:
Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children
We can write:
(x + y + a + b + c)/5 = 38
But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54
Substitute this value to our first equation
(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136
Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2
But x + y = 136
=> mean age = 136/2 = 68
Answer:
E
Step-by-step explanation:
Solution:-
- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.
- The survey team took a sample of size n = 24 students and obtained the following results:
Sample mean ( x^ ) = 12.3 mins
Sample standard deviation ( s ) = 3.2 mins
- The sample taken was random and independent. We can assume normality of the sample.
- First we compute the critical value for the statistics.
- The z-distribution is a function of two inputs as follows:
- Significance Level ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025
Compute: z-critical = z_0.025 = +/- 1.96
- The confidence interval for the population mean ( u ) of walking times is given below:
[ x^ - z-critical*s / √n , x^ + z-critical*s / √n ]
Answer: [ 12.3 - 1.96*3.2 / √24 , 12.3 + 1.96*3.2 / √24 ]
Answer: C
ABCD may or may not be a parellolgram. Line BD bisects line AC, however we cant figure out if line AC bisects line BD.
Answer:
52
Step-by-step explanation:
3^3+3(3)^2-7(3)+19
27+27-21+19
54-2
52
Hope this helps
Answer:
Please see attachment
Step-by-step explanation:
Please see attachment
