The answer to the question is 90
Decimals that contain a zero in the tenth position can be thought of as a fraction over 100 as the tenth isn't occupied and the hundredth correlates to the 100 as a denominator. The same goes for a number with the tenth position occupied. These decimals would be put over 10 as they are occupying that position in the decimal.
Step-by-step explanation:
We need to find each of the following as a rational number in the form of p/q
(a) (3/7)² (b) (7/9)³ (c) (-2/3)⁴
Solution,
(a) (3/7)²
(b) (7/9)³
(c) (-2/3)⁴
Hence, this is the required solution.
U want to go x2 plus x so its x3 then 4x3times -15 so x=3.33333
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.