Answer:
look at the picture i have sent
From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.
Answer:
C. g(x) = 4x²
Step-by-step explanation:
The general equation for a parabola is
y = ax² + bx +c
Since ƒ(x) = x², a=1, b =0, c =0
For g(x), the vertex is still at the origin, so
g(x) = ax²
The graph passes through (1,4).
Insert the coordinates of the point.
4 = a(1)²
a = 4
g(x) = 4x²
The figure below shows that the graph of g(x) = 4x² passes through the point (1, 4).