What is the value of the expression 3y−zy+5z3y−zy+5z when y = 6 and z = 2?
2 answers:
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3sinx+1=sinx
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 =
/6 (when finding the inverse, always take the positive value, ignore the negative sign)
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7/6
360-3=330 = 11/6
2sinx+1=0
2sinx=-1
sinx=-1/2
x=sin^-1 (1/2) = 30 =
x is therefore negative in 3rd and 4th quadrant
Therefore values of x are:
180+30=210 = 7
360-3=330 = 11