Answer:
308°
Step-by-step explanation:
It's a Reflex angle more than 180° but less than 360°.......hope this helps have a great day/night
FACTOR ALL OF THE EQUATIONS INTO "y = (x-h)^2 + k," AND THE EQUATION'S VERTEX IS (h,k)
10. y = (x+2)^2 - 11 --> (-2, -11)
11. y = -(x-4)^2 + 32 --> (4, 32)
12. y = 3(x-1)^2 - 5 --> (1, -5)
13. y = -2(x+2)^2 + 5 --> (-2, 5)
14. y = 2(x+1)^2 - 1 --> (-1, -1)
15. y = -5(x-1)^2 + 8 --> (1, 8)
16. y = 3(x-3)^2 - 26 --> (3, -26)
17. y = (x+5)^2 - 32 --> (-5, -32)
18. y = -(x-3)^2 + 10 --> (3, -10)
If two angles are supplementary, their sum equals 180 degrees
Answer:
The value of x is 11
Step-by-step explanation:
<em>Two angles are complementary if the sum of their measures is 90°</em>
Let us use this rule to solve our question
∵ The angle of measure (3x)° and the angle of measure (5x + 2)°
are complementary angles
→ That means their sum equals 90°
∴ 3x + 5x + 2 = 90
→ Add the like terms in the left side
∵ (3x + 5x) + 2 = 90
∴ 8x + 2 = 90
→ Subtract 2 from both sides to move 2 from the left side to the right side
∵ 8x + 2 - 2 = 90 - 2
∴ 8x = 88
→ Divide both sides by 8 to find x
∵ 8x/8 = 88/8
∴ x = 11
∴ The value of x is 11
Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
