A honey bee flaps its wings 200 times per second. How much time is required for one wingbeat? Give your answer in milliseconds.

Physics

2 answers:

Schach [20]2 years ago

7 0

Answer:

The time is required for one wing beat is 5 millisecond.

Explanation:

Given that,

Frequency = 200 /sec

We need to calculate the time period

Using formula of time period

Time period is the reciprocal of the frequency.

$T=\dfrac{1}{f}$

$T=\dfrac{1}{200}$

$T=0.005\ sec$

$T= 5\ miliseconds$

Hence, The time is required for one wing beat is 5 millisecond.

kakasveta [241]2 years ago

3 0

A bees wings move so rapidly that studying them, even seeing them, has proved difficult.
The honeybees have a rapid wing beat honeybee flaps its wings 230 times every second.

Therefore, a bee flaps its wings over 200 times in about 1ms

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➶ Hope This Helps You!

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