Any number inside the modulus sign becomes positive. This means and so we have,
Solving these gives us
However if we check the second solution in the original equation we obtain . This is false and so can't be a solution.
Therefore the only solution is .
(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)
Two events are occurring:
1) Rolling a die
Sample Space = {1,2,3,4,5,6}
Total number of outcomes in sample space = 6
Favorable outcomes = Odd number
Number of Favorable outcomes = 3
Probability of getting an odd number = 3/6
2) Tossing a coin
Sample Space = {H, T}
Probability of getting a head= 1/2
The probability of getting odd number and head will be the product of two probabilities, which will be = 3/6 x 1/2 = 3/12
Thus there is 3/12 = 1/4 (0.25 or 25%) probability of getting an odd number and a head in given scenario.
So correct answer is option C
4.5(8 - x) + 36 = 102 - 2.5(3x + 24)
36 - 4.5x + 36 = 102 - 7.5x - 60
72 - 4.5x = 42 - 7.5x
-4.5x + 7.5x = 42 - 72
3x = - 30
x = -30/3
x = -10 <===
Hope this helps!
Answer:
x=3
Step-by-step explanation:
AB+BC>AC
2x + 3 + x + 1 > x + 10
we correct like terms
2x + x + 3 + 1> x+ 10
3x + 4> x + 10
3x - x > 10-4
2x > 6
divide both sides by 2
2x÷2 > 6÷2
x = 3