The orthocenter is the point where the three altitudes meet.
sketch the graph and you will see that AB is a horizontal line, the altitude is a vertical line through the point (1,3), so the equation of this altitude is x=1
next, find another altitude. I'll use the altitude of BC.
the slope of BC is (6-3)/(4-1)=1, so the slope of the altitude, which is perpendicular to BC going through the point A (0,6), is -1, the equation of the altitude of BC is y=-x+6
the system of equation : x=1
y=-x+6
has a solution (1, 5)
the solution is where the two lines meet, the meeting point is the orthocenter.
Double check by find the equation for other altitude:
slope of AC: (3-6)/(1-0)=-3
slope of altitude of AC: 1/3
equation of altitude of AC: y=(1/3)x+b
the altitude of AC goes through point B (4,6), so we can find out b by plug x=4, y=6 in the equation: 6=(1/3)*4+b, b=14/3
y=(1/3)x+14/3
Is (1,5) also a solution to this equation? Plug x=1 in the equation, we get y=5, so yes, (1,5) is a point on the third altitude.
So 5x=30
then x= 30/5
and x=6
so the answer is last one !
Answer:
B. x
Step-by-step explanation:
The answer would be graph x. A function must be that one x value should only have one y value. graph w doesn't work since when you plug in 0, you get two y's. same thing with z. Y doesn't work since at x value of 3, it curves back so x value 2 has 2 y's. X is the only one that each x value has only one y.
B because distributive property goes like this:
a(b+c)
a(b)+a(c)
That's just an example though
