<u>Answer:</u> The half life of the reaction is 1190.7 seconds
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:
where,
k = rate constant of the reaction =
= half life of the reaction = ?
Putting values in above equation, we get:
Hence, the half life of the reaction is 1190.7 seconds
Answer:
The scientific laws have been well proven before they are published so it is difficult to prove mistakes
Explanation:
Explanation:
from the equation 1 mole of O2 will give 2 moles of H2O then 6.0 moles of O2 will give x
6.0*2 moles/ 1 mole
= 12 moles
this implies that, 6.0 moles of O2 will give = 12 moles of water
There are 237. 5 g of Sulfur,S in 475 g of SO2?
<h3 />
<h3>Calculation of grams of Sulfur</h3>
From the question, we can say that
- The molar mass of sulfur = 32 g/mol
- The molar mass of oxygen = 16 g/mol
Therefore,
The molar mass for SO2 = 32 + (16 × 2) g/mol = 64 g/mol
Now,
If 1 mole of SO2 contains 1 mole of S
Then 64 g of SO2, will contain 32g of S;
Such that
475 g of SO2 will give { } = 237. 5 g of Sulfur.
Learn more about molar mass here :brainly.com/question/18291695