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2 years ago

Help any one please?

Mathematics

1 answer:

AfilCa [17]2 years ago

5 0

A = (1/2)(8yd)(15yd) = 60 yd²

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4/5 of 40

algol [13]

4/5 of 40 = 32
1/3 of 3 = 1
1/3 of 15 muffins = 10 muffins

3 0

2 years ago

PLZ HELP

Alex

Answer:

The correct option is C ) 109.5°

Therefore,

$m\angle E=109.5\°$

Step-by-step explanation:

Given:

In Triangle DEF

d = 10

e = 18

f = 12

To Find

angle E = ?

Solution:

In Triangle DEF , Cosine Rule says

$\cos E=\dfrac{f^{2}+d^{2}-e^{2}}{2fd}$

Substituting the values we get

$\cos E=\dfrac{12^{2}+10^{2}-18^{2}}{2\times 12\times 10}$

$\cos E=\dfrac{-80}{240}=-\dfrac{1}{3}$

Therefore,

$\angle E=\cos^{-1}(-0.3333)$

$m\angle E=109.5\°$ ............As it is in Second Quadrant

Therefore,

$m\angle E=109.5\°$

4 0

2 years ago

Three rays have a common vertex on a line. Write and solve equations to find the measures of m and n

lukranit [14]

Answer:

n = 90 - 62

n = 28º

m = 180 - (62 + n + 27)

m = 180 - (62 + 28 + 27)

m = 180 - 117

m = 63º

5 0

2 years ago

Simplify the expression (128x^5/8x)^1/2

solong [7]

Answer: 4x'6

Step-by-step explanation:

Simplify x5 /8. Than, Equation at the end of step 1 : x5 ——) • x)1) ÷ 4 8

Step 2 : 2.1 16 = 24 (16)1 = (24)1 = 24 2.2 x6 raised to the 1 st power = x( 6 * 1 ) = x6

Step 3 : 24x6 Simplify ———— 4

Dividing exponents : 3.1 24 divided by 22 = 2(4 - 2) = 22

which brings us to our final answer above

5 0

2 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

4 0

2 years ago