All categories

2 years ago

In which situation is chemical energy being converted to another form of energy?

Physics

2 answers:

anygoal [31]2 years ago

8 0

<span>D. A burning candle. (chemical energy into energy of heat and light, i.e. thermal and wave)</span>

vladimir1956 [14]2 years ago

4 0

Answer: Option (D) is the correct answer.

Explanation:

When we burn a candle then combustion reaction takes place as it results in the formation of carbon dioxide gas and water in the form of vapors (stream).

Thus, we can conclude that when a candle is burnt then chemical energy gets converted to heat energy or light energy.

As due to this heat energy the wax starts to melt.

You might be interested in

In a fit of rage about distance learning, you throw your computer out the window with an initial velocity of 3 m/s and it breaks

lesya692 [45]

Answer:

9 m

Explanation:

i did the test and got 100%

3 0

2 years ago

Of the three forces acting on the rock as it slides down the bowl, which (if any) are constant and which are not? explain.

choli [55]

Answer

Hi,

The forces are; weight (gravity), Normal/centripetal force and friction. Force due to gravity is constant where as friction and centripetal are not.

Explanation

Weight is constant, given by the force of gravity on the object. The centripetal force is a function of the angles occurring between the velocity vector and the weight vector that is at right angle with the perpendicular line drawn from the surface. Friction is a function of the centripetal force thus it also varies.

Hope this helps!

6 0

2 years ago

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

emmasim [6.3K]

The intensity on a screen 20 ft from the light will be 0.125-foot candles.

<h3>What is the distance?</h3>

Distance is a numerical representation of the length between two objects or locations.

The intensity I of light varies inversely as the square of the distance D from the source;

I∝(1/D²)

The ratio of the intensity of the two cases;

$\rm \frac{I_1}{I_2} =(\frac{D_2}{D_1} )^2\\\\ \rm \frac{2}{I_2} =(\frac{20}{5} )^2\\\\ \frac{2}{I_2} =4^2 \\\\ I_2= \frac{2}{16} \\\\ I_2= 0.125 \ foot-candles$

Hence, the intensity on a screen 20 ft from the light will be 0.125 foot-candles

To learn more about the distance refer to the link;

brainly.com/question/26711747

#SPJ1

6 0

1 year ago

An object moves in the eastward direction at constant speed. A net force directed northward acts on the object for 5.0 s. At the

Pie

Answer: D

The final velocity of the object will be directed north of east

Explanation:

8 0

3 years ago

Read 2 more answers

The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90

s2008m [1.1K]

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

6 0

2 years ago