First we will find the 11th term
an = a1 + (n-1) * d
a11 = 12 + (11 - 1) * 5
a11 = 12 + 10 * 5
a11 = 12 + 50
a11 = 62
now we use the sum formula...
Sn = (n (a1 + an)) / 2
S11 = (11 (12 + 62)) / 2
S11 = (11 (74)) / 2
S11 = 814/2
S11 = 407
Brennan will have to take 8 more quizzes to get to 25
<h3>
Answer: Approximately 23.0 cm</h3>
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Work Shown:
a = 20.3
b = unknown
c = 30.7
Apply the pythagorean theorem to find b
a^2 + b^2 = c^2
(20.3)^2 + b^2 = (30.7)^2
412.09 + b^2 = 942.49
b^2 = 942.49-412.09
b^2 = 530.4
b = sqrt(530.4)
b = 23.0304146727757 value is approximate
b = 23.0
I rounded to one decimal place because the other values (20.3 and 30.7) were to one decimal place.
Answer:
n = 2/3
Step-by-step explanation:
