5/7^3 = 5(7^x) Thank you for helping!!
1 answer:
When solving this equation you get x = -3.
To solve this, simply follow the order of operations for solving.
----> start by dividing both sides by 5
-----> Now you can transform the front side of the equation to use negative exponents.
Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.
-3 = x
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Answer:
D
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
here (h, k) = (- 6, - 8), thus
(x + 6)² + (y + 8)² = r²
The radius is the distance from the centre to a point on the circle
Calculate r using the distance formula
r = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 6, - 8) and (x₂, y₂ ) = (0, 0)
r = =
=
= 10
Hence
(x + 6)² + (y + 8)² = 100 → D