Answer:
the new ones and the old ones that you didn’t delete
Step-by-step explanation:
The actual distance between the cities will be equal to 9.2 miles.
<h3>What is an arithmetic operation?</h3>
The four basic mathematical operations are the addition, subtraction, multiplication, and division of two or even more integers. Among them is the examination of integers, particularly the order of actions, which is crucial for all other mathematical topics, including algebra, data organization, and geometry.
As per the given data in the question,
Distance between Yappy city and quit city is 23 cm.
As per the conversion is given in the question,
5 cm = 2 miles
Then, the number of miles of distance will be,
x = (2 × 23)/5
x = 9.2 miles.
To know more about arithmetic operations:
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Process efficiency is a measure of the ratio of process outputs to inputs.
Answer:
Two imaginary solutions:
x₁=
x₂ =
Step-by-step explanation:
When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.
The discriminant gives us information on how the solutions of the equations will be.
- <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
- <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
- <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)
So now we will work with the equation given: 4x - 3x² = 10
First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0
So:
4x - 3x² = 10
-3x² + 4x - 10 = 0 will be our equation
with this information we have that a = -3 b = 4 c = -10
And we will find the discriminant:
Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>
To proceed to solve the equation we will use the general formula
x₁= (-b+√b²-4ac)/2a
so x₁ =
The second solution x₂ = (-b-√b²-4ac)/2a
so x₂=
These are our two solutions in the imaginary numbers.