The molar solubility is 7.4× M and the solubility is 7.4× g/L .
Calculation ,
The dissociation of silver bromide is given as ,
→ +
S
- S S
Ksp = [ ] [ ] = [S] [ S ] =
S = √ Ksp = √ 5. 5× = 7.4×
The solubility =7.4× g/L
The molar solubility is the solubility of one mole of the substance.
Since , one mole of is dissociates and form one mole of each and ion . So, solubility is equal to molar solubility but unit is different.
Molar solubility = 7.4× mol/L = 7.4× M
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Answer:
Explanation:
N and P will have similarity
Electronic configuration of N
2,5
1s²2s²p⁵
Electronic configuration of P
1s²2s²2p⁶3s²3p⁵
Electronic configuration bears similarity.
Both have 5 electrons in their outermost orbits . So they exhibit similarity in their properties. Both belong to the same 15 th group of periodic table.
Sr and Rb too bear much similarity . Both are strongly electro-positive metal , difference in their atomic no being only one.
Answer:
The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.
Explanation:
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have mass of copper = m = 25.3 g
Specific heat of copper = c = 0.385 J/g°C
ΔT = 39°C - 22°C = 17°C
Heat absorbed by the copper :
The heat needed to warm 25.3 g of copper from 22°C to 39°C is 165.59 Joules.
These substances can be separated by distillation, so your answer is A.
Answer:
C, 42g
Explanation:
In thermal equilibrium, both bodies (metal pellet and water) both have the same final temperature (46.3°C).
Assuming no heat is lost to surroundings,
the energy lost from metal pellet = energy gained for water
Since E = mc∆T
(energy = mass x specific heat capacity x temperature change)
mc∆T (metal pellet) = mc∆T (water)
100 x 0.568 x (116-46.3) = m 4.184 (46.3 - 23.8)
3958.96 = 94.14m
m = 42g