The least common multiple of each pair of the polynomial (5y² - 80) and
(y + 4) is equal to 5(y-4)(y+4).
As given in the question,
Given pair of the polynomial is (5y² - 80) and (y + 4)
Simplify the given polynomial using (a² -b²) = (a-b)(a +b)
(5y² - 80) = 5(y² -16)
⇒(5y² - 80) = 5(y² - 4²)
⇒(5y² - 80) = 5(y -4)(y + 4)
And (y + 4) = (1) (y+4)
Least common multiple = 5(y-4)(y+ 4)
Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).
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Answer:
7
Step-by-step explanation:
28 ÷ 16 = 1.75
1.75 × 4 = 7
The way I did it is by finding out how much bigger 28 is than 16 by dividing and then I multiplied the answer (1.75) by 4 to get the bigger answer. The problem is showing you that the triangles are the same just different sizes.
Answer:
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Step-by-step explanation:
hope it would help you...