Suppose that equation of parabola is
y =ax² + bx + c
Since parabola passes through the point (2,−15) then
−15 = 4a + 2b + c
Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c
Since parabola passes through the point (−3,−5), then
−5 = 9a − 3b + c
Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5
Solving it we get that
a = −2, b = −4, c = 1
Thus, equation of parabola is
y = −2x²− 4x + 1
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Rewriting in the form of
(x - h)² = 4p(y - k)
i) -2x² - 4x + 1 = y
ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)
iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)
iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)
v) -3(x + 7/6)² = y - 445/36
vi) (x + 7/6)² = -⅓(y - 445/36)
(Shifting -⅓ to RHS)
vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p)
So, after rewriting the equation would be -
(x + 7/6)² = 4(-⅛)(y - 445/36)
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I hope this is what you wanted.
Regards,
Divyanka♪
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Answer: x = 1 + 0.5c
Step-by-step explanation:
<h3>
is the simplified expression</h3>
<em><u>Solution:</u></em>
Given that,
We have to simplify
We can simplify the above expression by combining the like terms
Like terms are terms that has same variable with same exponent and same or different coefficient
From given,
Group the like terms
Thus the given expression is simplified
A square has 4 equal sides
use pythagroeas theorem since a square has 4 right angles
a^2+b^2=c^2
a=b because the sides are equal (11)
11^2+11^2=c^2
242=c^2
square root both sides
11√2=c
the diagonal legnth is 11√2 centimiters
<em><u>your </u></em><em><u>question:</u></em><em><u> </u></em>
solve 3√125=? by following steps above
<em><u>answer:</u></em>
<em>I'm</em><em> </em><em>not </em><em>sure </em><em>what</em> <em>the </em><em>steps</em><em>"</em><em> </em><em>are </em><em>but </em><em>I </em><em>got </em><em>33.54101966249 </em>