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2 years ago

9

Evaluate: g(x) = 3•2x+2 + 3 g(3)

1 answer:

Studentka2010 [4]2 years ago

6 0

Answer:23

Step-by-step explanation:

3·2（3）+2+3

=3·6+2+3

=23

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Whats the answer giving brainliest :))))) lol

n200080 [17]

Answer:

B

Step-by-step explanation:

1+1=2

But 2x has to stay the same

5 0

1 year ago

In Exercises 1-4, ill in the blank.

EleoNora [17]

1. Supplementary

2. Complementary

3. Adjacent angles

4. Vertically opposite angles

Hope it helps. Please mark brainliest.

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2 years ago

Find the surface area of a right cone with diameter 30 in. and slant height 8 in.Your answerEXTRA CREDIT: Find the surface area

Anon25 [30]

<u>Answer:</u>

Surface area = 1084 in²

<u>Step-by-step explanation:</u>

To find the surface area of a right cone, we can use the following formula:

$\boxed{{Area = \pi r^2 + \pi rl}}$ ,

where:

• r = radius

• l = slant height.

In the question, we are told that the diameter of the cone is 30 in. Therefore its radius is (30 ÷ 2 = ) 15 in. We are also told that its height is 8 in.

Using this information and the formula above, we can calculate the surface area of the cone:

Surface area = $\pi \times (15)^2 + \pi \times 15 \times 8$

= $345 \pi$

$\approx$ 1084 in²

6 0

11 months ago

Help!! 50 points and brainliest!

Viktor [21]

Answer:

Second choice:

$x=2t$

$y=4t^2+4t-3$

Fifth choice:

$x=t+1$

$y=t^2+4t$

Step-by-step explanation:

Let's look at choice 1.

$x=t+1$

$y=t^2+2t$

I'm going to subtract 1 on both sides for the first equation giving me $x-1=t$ . I will replace the $t$ in the second equation with this substitution from equation 1.

$y=(x-1)^2+2(x-1)$

Expand using the distributive property and the identity $(u+v)^2=u^2+2uv+v^2$ :

$y=(x^2-2x+1)+(2x-2)$

$y=x^2+(-2x+2x)+(1-2)$

$y=x^2+0+-1$

$y=x^2$

So this not the desired result.

Let's look at choice 2.

$x=2t$

$y=4t^2+4t-3$

Solve the first equation for $t$ by dividing both sides by 2:

$t=\frac{x}{2}$ .

Let's plug this into equation 2:

$y=4(\frac{x}{2})^2+4(\frac{x}{2})-3$

$y=4(\frac{x^2}{4})+2x-3$

$y=x^2+2x-3$

This is the desired result.

Choice 3:

$x=t-3$

$y=t^2+2t$

Solve the first equation for $t$ by adding 3 on both sides:

$x+3=t$ .

Plug into second equation:

$y=(x+3)^2+2(x+3)$

Expanding using the distributive property and the earlier identity mentioned to expand the binomial square:

$y=(x^2+6x+9)+(2x+6)$

$y=(x^2)+(6x+2x)+(9+6)$

$y=x^2+8x+15$

Not the desired result.

Choice 4:

$x=t^2$

$y=2t-3$

I'm going to solve the bottom equation for $t$ since I don't want to deal with square roots.

Add 3 on both sides:

$y+3=2t$

Divide both sides by 2:

$\frac{y+3}{2}=t$

Plug into equation 1:

$x=(\frac{y+3}{2})^2$

This is not the desired result because the $y$ variable will be squared now instead of the $x$ variable.

Choice 5:

$x=t+1$

$y=t^2+4t$

Solve the first equation for $t$ by subtracting 1 on both sides:

$x-1=t$ .

Plug into equation 2:

$y=(x-1)^2+4(x-1)$

Distribute and use the binomial square identity used earlier:

$y=(x^2-2x+1)+(4x-4)$

$y=(x^2)+(-2x+4x)+(1-4)$

$y=x^2+2x+-3$

$y=x^2+2x-3$ .

This is the desired result.

3 0

2 years ago

Read 2 more answers

Identify the property used in the following<br>a+b=b+a<br>(ab)c =a(bc)

KATRIN_1 [288]

Answer: The first one is Commutative Property

The second one is associative property

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers