Equation 1: -x-y = 1y, -x = 2y
Equation 2: 1y = x+3 , y = x+3
Substitute equation 2 into equation 1
-x = 2y
-x = 2(x+3)
-x = 2x + 6
-3x = 6
x = -2
Substitute x=-2 into equation 2
y = x+3
y = -2+3
y = 1
So, (x,y) = (-2,1)
Given that th<span>e coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) and the coordinates of the vertices of △D′E′F′ are D′(0, −1) , E′(−5, −1) , and F′(0, −3) .
Notice that the y-coordinates of the pre-image and that of the image are the same, which means that there is a reflection across the y-axis.
A refrection across the y-axis results in the change in sign of the x-coordinates of the pre-image and the image while the y-coordinate of the image remains the same as that of the pre-image.
A refrection across the y-axis of </span>△DEF with vertices D(2, −1) , E(7, −1) , and F(2, −3)
will result in and image with vertices (-2, -1), (-7, -1) and (-2, -3) respectively.
Notice that the x-coordinate of the final image △D′E′F′ with vertices <span>D′(0, −1) , E′(−5, −1) , and F′(0, −3) is 2 units greater than the vertices of the result of recting the pre-image across the y-axis.
This means that the result of refrecting the pre-image was shifted two places to the right.
Therefore, </span>the sequence of transformations that maps △DEF to △D′E′F′ are reflection across the y-axis and translation 2 units right.
Answer:
D. The y-intercept of the new graph would shift down 2 units.
Step-by-step explanation:
y = -9x + 3 has a y-intercept of 3 (0, 3).
y = -9x + 1 has a y-intercept of 1 (0, 1).
3 - 1 = 2
So, down two units.
Answer:
Step-by-step explanation:
This quadratic models the parabolic motion equation
where h is the height of the object after the motion occurs, a is the pull of gravity, v(i) is the initial vertical velocity of the object, and h(i) is the height from which the object was initially launched. If we are looking for when the ball hits the ground, h = 0, because the height of an object on the ground has no height at all (or 0 height). To find the time the object was in the air, factor the quadratic and solve for the values of t.
Two factors of 4 that add up to be 3 and multiply to be 4 are -1 and 4. So t=-1 and t = 4. Since we know that time can never be negative, then t = 4 seconds.
D= 5c
c is the number of customers and for every customer, Jenny earns d dollars.