if indeed two functions are inverse of each other, then their composite will render a result of "x", namely, if g(x) is indeed an inverse of f(x), then
![\bf (g\circ f)(x)=x\implies g(~~f(x)~~)=x \\\\\\ \begin{cases} f(x) = 3x\\ g(x)=\cfrac{1}{3}x \end{cases}\qquad \qquad g(~~f(x)~~)=\cfrac{1}{3}[f(x)]\implies g(~~f(x)~~)=\cfrac{1}{3}(3x)](https://tex.z-dn.net/?f=%5Cbf%20%28g%5Ccirc%20f%29%28x%29%3Dx%5Cimplies%20g%28~~f%28x%29~~%29%3Dx%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20f%28x%29%20%3D%203x%5C%5C%20g%28x%29%3D%5Ccfrac%7B1%7D%7B3%7Dx%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20g%28~~f%28x%29~~%29%3D%5Ccfrac%7B1%7D%7B3%7D%5Bf%28x%29%5D%5Cimplies%20g%28~~f%28x%29~~%29%3D%5Ccfrac%7B1%7D%7B3%7D%283x%29)
Use A = P (1 + r/n) ^(nt). Assuming that we're dealing with years here, n = 1, so we have
A = P (1 + r) ^(t), where r is the interest rate as a decimal fraction.
The investment decreases in value, so the common ratio r is (1.000-0.012), or 0.988.
Thus, A = $100,000* (0.988) ^25 = $73947.52 is the current value, after 25 years.
In:ft
3:4
x:24--- to find x, multiply each side by 6, because 24/4=6
3*6:24
18:24
The length of the object is 18 in. I think this is what your asking, but I'm not sure because I didn't quite understand the wording on the problem.
